Given are the 5 data units of 7 bits each, you have to find the value of parity bit (Both odd and even) for
each data unit:
Data Unit Even Parity bit Odd Parity bit
1001011
1010111
1100100
1011100
1111011
Question No. 2 [10 Marks]
Let us consider a point to point network having 9 computers. Answer the following questions with
complete calculations.
a) How many connections/links will be needed in order to connect these computers with each other in
this point to point network?
b) How many new connections/links will be needed in order to add a new machine in this network
Solution:
Question No.
Given are the 5 data units of 7 bits each, you have to find the value of parity bit (Both odd and even) for each data unit:
Solution:
|
Data Unit
|
Even Parity bit
|
Odd Parity bit
|
|
1001011
|
10010110
|
10010111
|
|
1010111
|
10101111
|
10101110
|
|
1100100
|
11001001
|
11001000
|
|
1011100
|
10111000
|
10111001
|
|
1111011
|
11110110
|
11110111
|
Question No. 2
Let us consider a point to point network having 9 computers. Answer the following questions with complete calculations.
a) How many connections/links will be needed in order to connect these computers with each other in this point to point network?
Solution:
=(n^2-n)/2
= (81-9)/2
=72/2=36
a) How many new connections/links will be needed in order to add a new machine in this network?
Solution:
N-1=9-1=8
