Assignment No. 1
(Non-Graded)
Semester Fall 2013
Digital Logic and Design – CS302
Digital Logic and Design – CS302
Total Marks: 20
Due Date: 20thNov 2013
Objective:
The assignment has been designed to develop the understanding related to the followings:
- Conversion
- Logic gates
Instructions:
Please read the following instructions carefully before solving & submitting assignment:
It should be clear that your assignment will not get any credit (zero marks) due to followings,
- The assignment is submitted after due date.
- The submitted assignment does not open or file is corrupt.
- The assignment not submitted in MS Word file format.
- The assignment is copied (from other student or copied from handouts or internet).
- Student ID is not mentioned in the assignment file or name of file is other than student ID.
For any query about the assignment, contact only at CS302@vu.edu.pk
Do not post queries related to assignment on MDB.
GOOD LUCK
Question 1 [5 Marks]
Convert the following caveman numbers into decimal numbers by performing all the steps.
(a) ∑ ↑ Ω
(b) ↑ ∆ ∑ ∑
(Show complete conversion steps)
Question 2 [5Marks]
Convert binary code 11101110 to Gray code by showing all steps of conversion and mention which method is used for conversion?
(Show complete conversion steps)
Question 3 [10Marks]
Following two waves are applied at 2-input NAND and NOR gates. Draw the output waveform of both gates.
Idea Solution :
Question No. 1
(a) Given caveman numbers are
∑ ↑ Ω
We have to convert them in decimal numbers
∑ ×52 + ↑ × 51 + Ω × 50
= ∑ × 25 + ↑× 5 + Ω × 1
By replacing the caveman numbers with equivalent decimal values in the expression
∑ × 25 + ↑× 5 + Ω × 1 = (0) × 25 + (4) × 5 + (3) × 1
= 0 + 20 + 3
= 20 + 3 = 23
(a) Given caveman numbers are
∑ ↑ Ω
We have to convert them in decimal numbers
∑ ×52 + ↑ × 51 + Ω × 50
= ∑ × 25 + ↑× 5 + Ω × 1
By replacing the caveman numbers with equivalent decimal values in the expression
∑ × 25 + ↑× 5 + Ω × 1 = (0) × 25 + (4) × 5 + (3) × 1
= 0 + 20 + 3
= 20 + 3 = 23
